MESO-Rx Sponsor Primal Pharma - US Domestic

[dinfar1337]

That's what the first post states in this thread states. Just wanted to confirm with vendor. Thank you.



You may enjoy this...

https://pubs.acs.org/doi/abs/10.1021/jo00244a027

We will get to the bottom of the potential interference issue. Good to get this figured out so we don't have revisit every year.

MeOH reacts with anadrol

meoh 99% reacts with anadrol

filtered from particulate and tested.

filter the solid baking soda out because it didnt react to the MeOH which mr jano has 99.9% of and theres no water in it to react with the baking soda.

now there is only oxy left.

enjoy the breakdown, the anadrol was 32mg.

the anadrol was never put in high heat conditions with the baking soda. it was filtered out from the start

 

[BigDadd7]

Man the PIP from the Sustanon 500 MCT has been crazy. I've pinned all sorts of high concentration stuff (Bold CYP 300, Test CYP 400, Test D 600, etc.) but never gotten pip like this. Tried it 3 times with 0.5ml subq (I always test subq before IM with new sources). All 3 times ended up with HUGE red lumps. One is so big now I can fit my whole hand around it (the other 2 thankfully are dissipating). I'm hoping the Test E 500 isn't this way cause I got way more of that than I did the Sust... Tren E 400 only using 0.1ml (and cut it with low concentration test D) ended up with PIP as well. I've never been someone that's even considered pip a part of the equation before, especially with SUBQ. I just thought people were sensitive. When people gave PIP reports on a source I'd ignore it because I've never been crippled with pip. This sust is another beast though...

I'll come back with a pip report on the Test E incase anyone cares to know. Really hope it works out cause I got a ton of the Test E vials

The test 500 is going to burn the same way. Pinning something like that subq is nuts. Most people mix the high concentration stuff with whatever else they're running.

 

[JBird99]

Bottles:

https://a.co/d/hYKcI60

O2 absorbers:

https://a.co/d/e5zqlbT

Dessicant packs:

Amazon.com

Thank you again! Hope you had a sick workout!

 

[JoeTrogan]

The test 500 is going to burn the same way. Pinning something like that subq is nuts. Most people mix the high concentration stuff with whatever else they're running.

I'm trying to run test only and minimize shot volume... I've done all the other compounds and concentrations I mentioned subq (as well as IM). I'll probably just try cutting down the concentration with oil.

 

[newguy2]

Pretty sure that's the fill in all their caps. That's what it tastes like dripping down the back of my nose, anyway.

Bro you wild!! I lol'd at this hard.

 

[Photon]

I'm trying to run test only and minimize shot volume... I've done all the other compounds and concentrations I mentioned subq (as well as IM). I'll probably just try cutting down the concentration with oil.

Mix it with Test D or BU if u run that

 

[AlexDavis43]

Would be really productive to have a separate badge for folks who contribute to the group testing thread. Obviously that has to be verified somehow. That MESO actively supports improved testing and standards for the UG (and provides a space to encourage it) is what separates it from the pack as far as AAS forums go.

Seems like another way to increase divisiveness among members

"I donated to the testing fund, I'm better than you, hashtag harm reduction" etc

Getting rid of elite status tags was a good move imo, more like we're all on the same page (you can still look up someone's join date if that's important to you)

 

[readalot]

meoh 99% reacts with anadrol

filter the solid baking soda out because it didnt react to the MeOH which mr jano has 99.9% of and theres no water in it to react with the baking soda.

now there is only oxy left.

enjoy the breakdown, the anadrol was 32mg.

the anadrol was never put in high heat conditions with the baking soda. it was filtered out from the start

Baking soda has some decent solubility in MeOH.

https://pubs.acs.org/doi/10.1021/je60030a009

Does this affect the MeOH-oxymetholone adduct configuration and hence HPLC result? See paper posted above (post 9580).

 

[dcfreak]

I've got about 3,000ish Anavar and 3,700 Anadrol, but they're literally all from one source, same with the Winstrol, so not much use for testing, unfortunately. If you show up in force, I'll give up some Avanar, my kidney problems mean I probably won't be able to use all that I have anyhow, unfortunately. Not a huge fan of orals anyhow

Thank you for making me feel better.

I thought *my* stash was excessive lol

 

[dinfar1337]

Baking soda has some decent solubility in MeOH.

baking soda is insoluble in MeOH, both chemically and in pratice.

Just looking up the reports its 2% at 22c. you should get most of that stuff out and jano is probably on the low end of this. he isnt using alcohol with water in it, he is using 99% alcohol for chemical use.

that whole paper is useless since we arent using alcohol-water which means we have almost no reaction with the baking soda at all.

https://pubs.acs.org/doi/10.1021/je60030a009

Does this affect the MeOH-oxymetholone adduct configuration and hence HPLC result? See paper just posted.

i would say no, a little Na H C O3 wont be near fully ionized the way it would be in a protic solvent.

i read your paper and the reports on anadrol overall would be completely skewed from jano then.

in reality baking soda reacts so little only 2% to MeOH, but it still only ionizes at 1%. so if i even gave u 15% to work with you would still end up doing the molar mass calculations to be affected of total than less 1mg for 50mg oxy pill even if it had 1g(atleast 5-6 times higher than a normal oxy pill) of baking soda.

jano is accurate and the pill is underdosed is 99.9999% the case here but primal pharma can go do further testing on it if he thinks that isnt the case

 

[AllGoodThings]

Thank you for making me feel better.

I thought *my* stash was excessive lol

Excessive? What's that mean?

 

[dinfar1337]

that whole paper is useless since we arent using alcohol-water which means we have almost no reaction with the baking soda at all.

 

[readalot]

baking soda is insoluble in MeOH, both chemically and in pratice.

Uh no. Last row of first data set in Table 1 shows about 2% solubility at 22 deg C (baking soda in pure MeOH).

Just looking up the reports its 2% at 22c. you should get most of that stuff out and jano is probably on the low end of this. he isnt using alcohol with water in it, he is using 99% alcohol for chemical use.

Correct. Table 1 shared shows the limiting case of no water, just MeOH as solvent.

that whole paper is useless since we arent using alcohol-water which means we have almost no reaction with the baking soda at all.

Respectfully disagree. Water is non issue. See limiting MeOH only case.

i would say no, a little Na H C O3 wont be near fully ionized the way it would be in a protic solvent.

We would need to invoke completely ionization to construct a plausible interference mechanism?

i read your paper and the reports on anadrol overall would be completely skewed from jano then.

in reality baking soda reacts so little only 2% to MeOH,

MeOH doesn't react; it is solvent for baking soda.

but it still only ionizes at 1%. so if i even gave u 15% to work with you would still end up doing the molar mass calculations to be affected of total than less 1mg for 50mg oxy pill even if it had 1g(atleast 5-6 times higher than a normal oxy pill) of baking soda.

Think about the mg of anadrol in one capsule and corresponding amount of baking soda that would be present in the MeOH at 2% solubility. What is their molar ratio?

Does the baking soda need to ionize fully to interfere with adduct?

Thanks for your comments.

jano is accurate and the pill is underdosed is 99.9999% the case here but primal pharma can go do further testing on it if he thinks that isnt the case

Jano mentioned the issue with baking soda and anadrol hence why we started discussing this.

 

[readalot]

View attachment 352906

Keep going down further on front page to first data set in Table 1. See last row. Limiting case with no water...

2.13 wt% baking soda in 97.87 wt% MeOH.

 

[Tdeck81]

@readalot @dinfar1337 @Photon

I think I’m grasping the general scientific principles you’re using to validate the Jano testing, but it is highly confusing for me. Is it fair to say it’s virtually impossible for the testing +/- to be so great that a 50mg Anadrol pill would test as 32mg?

 

[dinfar1337]

Keep going down further on front page to first data set in Table 1. See last row. Limiting case with no water.

brother.

this is solubility in water methanol.

theres solution, compisition, water %.

we're already starting off with 9.71% water in the alcohol which is the probleim im pointing out.

baking soda is solube in 99% alcohol at a very small percatange. if u did pure ethanol it would be 0%

 

[readalot]

brother.

this is solubility in water methanol.

theres solution, compisition, water %.

we're already starting off with 9.71% water in the alcohol which is the probleim im pointing out.

baking soda is solube in 99% alcohol at a very small percatange. if u did pure ethanol it would be 0%

View attachment 352909

Respectfully, you are looking at the wrong row. Final row has no water. See the ternary chart on second page (Fig. 1 if that helps). Each row is an independent composition. The last row is MeOH, no water.

 

[k710]

Sorry to interupt all the nerd talk BUT you guys have been glazing primal and his products so hard that I had to go ahead and get my order in. Was waiting for test-c (and wishfully hoping for mast e) but I couldnt wait any longer. Was afraid the mast prop was going to go OOS and I needed some reta lol Plus had to take advantage of btc at ath


Ill be patiently waiting for my bananas.. well not too patiently, ill prob start throwing poop at the mailman if he shows up around here without my nanners

 

[dinfar1337]

MeOH doesn't react; it is solvent for baking soda.

right, my language sucks. it dissolves at 2%

Think about the mg of anadrol in one capsule and corresponding amount of baking soda that would be present in the MeOH at 2% solubility. What is their molar ratio?

Does the baking soda need to ionize fully to interfere with adduct?

Thanks for your comments.

dissolved baking soda per pill if we use 1ml MeOH

20mg

molar mass of anadrol at 50mg 306g/mol

molar mass of baking soda at 20mg(max dissolved possible) 84g/mol


the molar ratio is 1.5

account for ionization.

molar ratio is now 0.015.

you will have 1.5% of 50mg that can potentially see a bicarbonate ion.

0.75mg is possibly wrong on the test.

not 50mg-32mg.

thats atleast how i did the calculations

 

[dinfar1337]

Respectfully, you are looking at the wrong row. Final row has no water. See the ternary chart on second page (Fig. 1 if that helps). Each row is an independent composition. The last row is MeOH, no water.

ah i see now its reverse of what i was thinking.

thats me not reading properly.

its methanol percantange. and h2o is the water. funny how i included that in the screenshot and i was the one who didnt read xd