Agree with your math and your setup with 1 ml of MeOH. Now go back and look at the reaction of MeOH and oxymetholone in the kinetics paper I shared. What is the other product made in equimolar amount to the MeOH-oxymetholone adduct?right, my language sucks. it dissolves at 2%
dissolved baking soda per pill if we use 1ml MeOH
20mg
molar mass of anadrol at 50mg 306g/mol
molar mass of baking soda at 20mg(max dissolved possible) 84g/mol
the molar ratio is 1.5
account for ionization.
molar ratio is now 0.015.
you will have 1.5% of 50mg that can potentially see a bicarbonate ion.
0.75mg is possibly wrong on the test.
not 50mg-32mg.
thats atleast how i did the calculations
See eqn. 1, p. 1994.


