Shit, I misread your statement but realized it after I wrote all of this. I’ll be damned if I’m going to erase it.
So you are referring to the continuity equation. Which is basically the idea of the conservation of mass in this situation. Q is not reduced by going to a larger diameter needle. The velocity is reduced.
Because we are in a closed system and dealing with an incompressible fluid. The mass in has to equal the mass out, once the system has reached steady state.
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Q is the volumetric flow rate. The assumption made is that the thermal losses are not enough to change the density of the fluid. If this assumption is not correct, this problem just got a lot more complicated. I do love me some heat transfer though. The p looking letter in the above picture is the Greek letter Rho and in fluid dynamics is used for density. Since the density is not changing it cancels out on both sides. That leaves A1V1=A2V2
From the continuity equation, Q=AV(I can expand on this if requested). So it can be written as Q1=Q2. The only way for that equation to be true is if the flow rate stays the same.
As stated originally, I can not speak to the effects of the turbulence on aggregation. I know nothing about this. I only wanted to provide information on the sources of shear stress in flow through a pipe. I will go back and look at your reference.
I do enjoy this topic and don’t mind expanding further if anyone wants to know more.