Mass Spec Thread

250 mg of test E is the same. 98% or 100% or 50% purity, you are still getting 250mg of test E.
The question is, what else are you getting with that 2% or 50% of unknowns.
 
250 mg of test E is the same. 98% or 100% or 50% purity, you are still getting 250mg of test E.
The question is, what else are you getting with that 2% or 50% of unknowns.
You're getting NOT TEST E, with that other %.. that's what you're getting
So, how is it looked at as Test E when it's not?

HG isn't 100%, so what are the impurities, in HG gear?
Cyanide? Heavy Metals?
 
So, doubling a 50% purity gear, won't
ever give same results as a 98% gear. Correct

I think you would still have a 50% pure gear unless you were able to remove the unwanted 50% before doubling it. When you double it you are doubling the good 50% and the bad 50% so you just have twice the amount but still only 50% pure.
 
You are doing extra math.
There was no powder tested, just the finished product.
The concentration of the finished oil is 202mg/ml or 80% of advertised concentration.
How does this math add up 80% but it is 68% pure.
I will wait for someone who knows there shit because from what I gather you have a concentration of 202 of whats left and it is 68% pure of that.
Not saying I am right here. But burr your math doesn't add up.
 
Let's compare to Breaking bad
Jessie make some meth, and has 80% purity. He's just not that good of a chemist. There are some leftover compounds in his meth that should have been removed during the refining process, plus a little cayenne pepper.

Heisneberg makes his meth, and has it all perfect, comes out at 98% purity.

Now suppose you want to buy your meth dissolved in oil.
Your vial says 100mg of meth per ml.
Heisenburg would add 1010mg of his meth to 10ml of oil, and be dosed at 100mg
Jessie could add 1200mg of his meth to 10ml of oil and be dosed at 100mg

The purity does not change the final dose of meth.
 
Yes exactly that is why it is 67% pure of the 202. BTW never watched breaking bad. If there was 202mg out of the 250mg it would be 80% pure. Lets just talk the numbers at hand. 250 and 202. If I am frustrating you sorry for my ignorance I just asked a few people I know and they say I am right. Not pretending this is my arena at all. Just help me understand how 202 and 250 works to 67%.
 
Purity and concentration are two different things.
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I got to go catch back on this in a bit. Ok for now I think you will have to convince lightspan later as for me I will watch you guys hash itout.
 
Yes Purity and Dose are different, but
I just want to know if taking a 98% purity to 255mg
gives same results, as a 100% purity at 250mg...

Unless the purity is in the Test Molecule itself, I say YES
 
If I have Test E in powder form, at 68% purity and I want to make full dose vials at 250mg/ml
I would add 367mg of powder to a ml of oil. 367x.68= 250

If Titan adds 297 mg of the same powder to 1ml of oil, he gets 202 mg/ml oil

Assuming his oil was pure, his final product would still be 68% purity.
 
If I have Test E in powder form, at 68% purity and I want to make full dose vials at 250mg/ml
I would add 367mg of powder to a ml of oil. 367x.68= 250

If Titan adds 297 mg of the same powder to 1ml of oil, he gets 202 mg/ml oil

Assuming his oil was pure, his final product would still be 68% purity.

Wouldn't the powder take up some space too? Lets say that 297mg takes up .1ml then wouldn't you add that to .9ml of oil so that the outcome is 1ml?
 
If I have Test E in powder form, at 68% purity and I want to make full dose vials at 250mg/ml
I would add 367mg of powder to a ml of oil. 367x.68= 250

If Titan adds 297 mg of the same powder to 1ml of oil, he gets 202 mg/ml oil

Assuming his oil was pure, his final product would still be 68% purity.
Well this lines up to what he told me but I always thought the way voltrader said it was right.
 
Wouldn't the powder take up some space too? Lets say that 297mg takes up .1ml then wouldn't you add that to .9ml of oil so that the outcome is 1ml?
yes. You are correct. Just harder math to use as example.
 
If Titan adds 297 mg of the same powder to 1ml of oil, he gets 202 mg/ml oil
Assuming his oil was pure, his final product would still be 68% purity.

I think I get what you're saying now, because the oil is more or less excluded from the sample, so what is tested is 68% test E and 32% unknown.
 
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