Test e lab synthesis

considering the relative ease and availability of high purity test e raws, why go through this effort?
Post count and likes.

I did this in 2014 just to test my knowledge gathering skills. Its been sitting in my computer folder alongside other drugs.

I never used it, cuz pharma didn't hire

If there's no demand the topic will naturally die off

The next post will be the sort of the keystone step imo.

Will post if the number of likes increases
 
You have two ketone.
sodium borohydride reduces both aldehyde and ketone. You have no aldehyde group in 4-ad. So you have to protect ketone on position 3
 
You have two ketone.
sodium borohydride reduces both aldehyde and ketone. You have no aldehyde group in 4-ad. So you have to protect ketone on position 3
IMG_20241116_093202.webp

Never tried it, i wouldn't know. The info i have, is old. Things change.

Must be nice to be able to be a roid chemist

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You know what aldehyde and ketone means?
Aldehyde is in general more reactive because of less steric hinderence. There is teo R groups attached to ketone while aldehyde has one R group and one hydrogen which is way smaller.
4-ad does not contain any aldehyde. You are mixing everything together
 
You know what aldehyde and ketone means?
Aldehyde is in general more reactive because of less steric hinderence. There is teo R groups attached to ketone while aldehyde has one R group and one hydrogen which is way smaller.
4-ad does not contain any aldehyde. You are mixing everything together
That is true, but in this case the ketone involved is an enal. That's a conjugated bond.

So yes there is a difference.

We are not making test from simple acetone or aldehyde.

You have swiftly turned a cyclic compound into a linear planar one, just to get a emotional reaction.
 
You know what aldehyde and ketone means?
Aldehyde is in general more reactive because of less steric hinderence. There is teo R groups attached to ketone while aldehyde has one R group and one hydrogen which is way smaller.
4-ad does not contain any aldehyde. You are mixing everything together
You are reducing the ketone group at 17 position. Under same conditions, the ketone group will be reduced too. If i am not wrong, the ketone group at 3 position is less reactive because of stability from the double bond than the other ketone, but still reactive
 
You are reducing the ketone group at 17 position. Under same conditions, the ketone group will be reduced too. If i am not wrong, the ketone group at 3 position is less reactive because of stability from the double bond than the other ketone, but still reactive
Not me, Dale.
He reports good selectivity with the conditions he tried in his paper, which is why i brought up the protective group issue.

Is simply I didn't know it was needed.
If it's needed it's good to know
IMG_20241116_093138.webp

Page 3
 
Not me, Dale.
He reports good selectivity with the conditions he tried in his paper, which is why i brought up the protective group issue.

Is simply I didn't know it was needed.
If it's needed it's good to know
View attachment 303376

Page 3
Mate, the study compares aldehyde with ketone. Not ketone with ketone
I am understanding you wrong correct me
 
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